8u^2+8u=48

Solution for 8u^2+8u=48 equation:

8u^2+8u=48

We move all terms to the left:

8u^2+8u-(48)=0

a = 8; b = 8; c = -48;
Δ = b2-4ac
Δ = 82-4·8·(-48)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-40}{2*8}=\frac{-48}{16}
=-3
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+40}{2*8}=\frac{32}{16}
=2
$